Question
Simplify.$$2-\left(3^{3}+16 \div(-2)^{3}\right)$$
Step 1
We have $3^{3}$ and $(-2)^{3}$. $$ 3^{3} = 3 \times 3 \times 3 = 27 $$ and $$ (-2)^{3} = -2 \times -2 \times -2 = -8 $$ So, the expression becomes: $$ 2-\left(27+16 \div -8\right) $$ Show more…
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