Question
Simplify. (a) $(-16)^{\frac{1}{4}}$ (b) $-16^{\frac{1}{4}}$(c)$16^{-\frac{1}{4}}$
Step 1
So, $(-16)^{\frac{1}{4}}$ is the fourth root of -16. However, it's impossible to take the fourth root of a negative number in real numbers. Therefore, $(-16)^{\frac{1}{4}}$ is a non-real number. Show more…
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