Question
Simplify and check using a graphing calculator.$$\frac{\sin ^{2} \theta-9}{2 \cos \theta+1} \cdot \frac{10 \cos \theta+5}{3 \sin \theta+9}$$
Step 1
From the second fraction, we can factor out a 5 from the numerator and a 3 from the denominator: $$\frac{\sin ^{2} \theta-9}{2 \cos \theta+1} \cdot \frac{5(2 \cos \theta+1)}{3( \sin \theta+3)}$$ Show more…
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