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Simplify. Assume that no variable equals 0.

$$

\left(\frac{c d}{3}\right)^{-2}

$$

$\frac{9}{c^{2} d^{2}}$

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McMaster University

Harvey Mudd College

Numerade Educator

Idaho State University

we're gonna simplify. See over D, divided by three. Race to the negative to power. So this negative too. We're going to distribute to the CD and 23 So we have C to the negative to power D to the negative to power and three to the negative to power. So to get rid of these negatives, what we have to do is we have to change the position of our CD and three. So if I put three on the top, that changes, it's signed, took positive. And if I put the c and D at the bottom, it changes their sign too positive so I can do three squared at the top over C squared times the square at the bottom. And I know three squared is nine and then c squared over d squared will stay the same at the bottom. So this is my expression simplified

University of North Texas