Question
Simplify by removing a factor equal to 1.$$\frac{24 x^{3} y}{30 x^{5} y^{8}}$$
Step 1
We can factor out 6, $x^{3}$, and $y$ from both the numerator and the denominator. This gives us: $$ \frac{24 x^{3} y}{30 x^{5} y^{8}} = \frac{6 \cdot 4 \cdot x^{3} \cdot y}{6 \cdot 5 \cdot x^{3} \cdot x^{2} \cdot y \cdot y^{7}} $$ Show more…
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