00:01
We're being asked to simplify the two given expressions.
00:02
So let's start with part a.
00:04
In this case, we're being asked to subtract two radicals.
00:07
The only way we can do that is if the radicans are the same.
00:10
So the first thing we need to do is try and simplify.
00:13
So let's start by looking at the first one.
00:15
So inside the radical, we have the square of the 10x squared.
00:18
Well, 10 is not a perfect square, and no perfect square divides into it evenly.
00:24
But the second part, we have the square root of x squared.
00:27
Well, that's simply just x.
00:28
So we can rewrite our first term as 5x times the square of the 10.
00:33
Now, for the second radical, we have the square of the 90x squared.
00:37
Well, 90 is not a perfect square, but 9 is a perfect square, and it goes into it 10 times.
00:43
So i'm going to rewrite this as the square root of 9 times the square of 10 times the square of x squared.
00:50
So i'm going to bring my first term down.
00:52
For my second one, we have the square over the 9, which is 3.
00:56
We can't take the square of the 10, so we leave that inside.
00:58
And the squares of x squared is just x.
01:01
Now that both of our radicans are the same, we can combine the coefficients.
01:06
So we're going to combine 5x minus 3x, which is 2x, and remember, the radicans will not change.
01:12
So our final answer to part a will be 2x times the square of the 10.
01:18
Now, very similar for part b...