Question
Simplify each expression. Then determine whether the given answer is correct.$$\frac{2-15 x-8 x^{2}}{64 x^{2}-1} ; \text { Answer: } \frac{x+2}{-8 x-1}$$
Step 1
The numerator can be factored by grouping and the denominator is a difference of squares which can be factored as follows: $$ \frac{2-15 x-8 x^{2}}{64 x^{2}-1} = \frac{-1(8x^2+15x-2)}{(8x-1)(8x+1)} $$ Show more…
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