Question
Simplify each rational expression.$$\frac{3 z^{4}+36 z^{3}+60 z^{2}}{3 z^{3}-3 z^{2}}$$
Step 1
In the numerator, we can factor out $3z^2$ and in the denominator, we can factor out $3z^2$ as well. This gives us: $$ \frac{3 z^{4}+36 z^{3}+60 z^{2}}{3 z^{3}-3 z^{2}} = \frac{3z^2(z^2+12z+20)}{3z^2(z-1)} $$ Show more…
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