00:01
All right, so we need to simplify this.
00:02
And it looks very complicated, but we can do it.
00:06
So i love these with the a cubed and there's an a squared and there's an a and there's a constant because i feel like it's a puzzle.
00:16
And so to solve for these, because there are even terms, i'm going to group these together.
00:25
I'm going to group these together.
00:28
Do the same with the denominator.
00:31
Okay, i'm grouping them in hopes that it turns out.
00:37
So in the first group, a -cube minus 2a -squared, what do they both have in common? they have an a -squared.
00:49
A -cubed, right, is a -times a times a times a.
00:54
If i take a squared out, i'm left with just a.
00:57
Subtract well two times a squared if i take the a squared out i have two left over plus now what can i factor with this second group well they both have a two in common two times a if i factor out i get an a subtract right four is two times two factor out a two i'm left with a look at this beautiful thing.
01:25
In both of those, my parentheses is the same thing.
01:29
A subtract 2.
01:31
That's what you want.
01:33
Because now what's outside the parentheses can be grouped together and what's inside the parentheses can be grouped together or combined together.
01:45
So that is our numerator...