The numerator can be factored using the difference of squares formula, $a^2 - b^2 = (a + b)(a - b)$. In this case, $a = m^x$ and $b = 1$. So, we have:
$$
m^{2x} - m^x - 2 = (m^x + 1)(m^x - 2)
$$
The denominator can also be factored using the difference of
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