Question
Simplify.$\frac{\sin (9 t)-\sin (3 t)}{\cos (9 t)+\cos (3 t)}$
Step 1
The formulas are as follows: \[\sin(A) - \sin(B) = 2\sin\left(\frac{A-B}{2}\right)\cos\left(\frac{A+B}{2}\right)\] \[\cos(A) + \cos(B) = 2\cos\left(\frac{A+B}{2}\right)\cos\left(\frac{A-B}{2}\right)\] Show more…
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