This means we raise each term inside the parentheses to the power outside the parentheses. For the first term, we cube $-\frac{2}{5}$, $c^{9}$, and $d^{2}$, and for the second term, we square $\frac{5}{4}$, $c$, and $d^{6}$.
$$\left(-\frac{2}{5} c^{9}
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