We have $\frac{-y^{3 / 2}}{y^{-1 / 3}}$. According to the rule of exponents, when we divide two exponents with the same base, we subtract the exponent in the denominator from the exponent in the numerator. So, we get $-y^{3/2 - (-1/3)} = -y^{3/2 + 1/3} =
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