Question

Simplify using the product and power rules. $\left(\frac{21 b^7}{14 a^5 c^2}\right)^4$ 

   Simplify using the product and power rules.
$\left(\frac{21 b^7}{14 a^5 c^2}\right)^4$
Intermediate Algebra with P.O.W.E.R. Learning
Intermediate Algebra with P.O.W.E.R. Learning
Sherri Messersmith,… 1st Edition
Chapter 6, Problem 54 ↓
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Simplify using the product and power rules. $\left(\frac{21 b^7}{14 a^5 c^2}\right)^4$
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Transcript

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00:02 To simplify this expression, first of all, i'm going to take advantage of the commutative property, which allows me to rearrange the order of the things i'm multiplying.
00:12 So i'm going to rearrange into the following order.
00:14 Negative 14 times 2, times a to the 5th, times a, times b, times c squared, times c to the 4th.
00:24 Now, you don't have to actually write them rearranged like this, but you can just think about it as this.
00:29 So negative 14 times 2 is negative 28.
00:32 And then for a to the fifth times a to the first, we add the powers on a and we get a to the sixth...
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