00:01
The velocity selector eliminates all ions not having the desired velocity.
00:06
Then the magnetic field bends the ions in a circular arc.
00:11
Now, in a velocity selector, the magnitude of electric field is equal to the magnitude of magnetic field.
00:19
And the direction are opposites, opposite for both the forces.
00:25
So the magnetic magnitude of the electric force is equal to the magnitude of the magnet of the magnetic force.
00:32
And so this gives q times e is equal to q times velocity times b.
00:38
There is no sign 5 because velocity and magnetic field are perpendicular.
00:46
So this gives the electric field to be v times the magnetic field.
00:53
So from here we can calculate the velocity which is equal to e over b.
00:57
And this is found to be so let's calculate that so for this case i forgot to write that this is for part b so for this case the electric the magnetic field is 0 .0315 tesla so we use that in this equation and we get the velocity to be 4 .92 times 10 to the power minus 3 meter per second...