00:01
Question number 118 wants you to sketch the titration curve for the di -functional base, ethylene -diamine, when titrated with a strong acid hcl.
00:18
So if it is a base, we are going to start out with a high ph and end up after the titration has occurred with a lower ph.
00:26
Because it is diffunctional, we are going to have two equivalence points.
00:32
To dramatic changes in ph.
00:35
Because we don't know the concentration of ethylene diamine that we are starting with, we can't calculate the ph at the equivalence points, but we can calculate the ph at the half equivalence points.
00:47
As you recall, ph is equal to pca at the half equivalence points, but we don't have an acid, so we don't have pca values, but we do have pkb values, and from those pkb values, we can calculate the pqa values.
01:03
The two kb values for ethylene diamine are 8 .5 times 10 to the negative 5 and 7 .1 times 10 to the negative 9.
01:13
We can calculate the pca values by recognizing that the ka1 value comes from the kb2 value.
01:22
So pka1 will be equal to because it's the p .a of the ka, it's the negative log of the ka value...