For the first set of parametric equations, we have $x = 3t - 4$ and $y = t + 5$.
When $t = -2$, we get $x = 3(-2) - 4 = -10$ and $y = -2 + 5 = 3$.
When $t = 2$, we get $x = 3(2) - 4 = 2$ and $y = 2 + 5 = 7$.
So, we have two points $(-10, 3)$ and $(2, 7)$.
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