For \(t = -4\), we get \(x = \frac{3(-4)}{1+(-4)^3} = -0.2\) and \(y = \frac{3(-4)^2}{1+(-4)^3} = -0.8\).
For \(t = -3\), we get \(x = \frac{3(-3)}{1+(-3)^3} = -0.3\) and \(y = \frac{3(-3)^2}{1+(-3)^3} = -1.1\).
For \(t = -2\), we get \(x =
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