00:01
For the first part of the problem, we have to understand that they are actually two half -cell reactions in this overall reaction.
00:09
It's completely unbalanced, by the way.
00:12
So you write down the two half -cell reactions like so, put down the reduction potentials, and then you multiply one of the half -cell reactions with a required number to equalize the number of electrons in both half -cells.
00:30
You do this because in a redox reaction, the number of electrons generated is the number of electrons that are taken up.
00:37
So you get a balanced equation here, which is my first order of business.
00:44
You get a balanced equation like so.
00:47
You can calculate the e -cell by subtracting the e -anod, which is this from the e -cathode, and you get a value of minus 2 .65.
00:59
Now, whichever side has oxidation occurring is the anode, and whichever side has reduction is the cathode.
01:08
So that was a second order of business.
01:10
Now, the third question is, what is the direction of electron flow? well, obviously, if the anode is dissociating and thereby giving off electrons, the electrons are going to travel from the anode to the cathode.
01:25
And the fourth thing is, for the salt bridge, the ion migration occurs towards the anode.
01:33
And this is because in case of the cathode, there are no charged species being produced...