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Sketch the graph of a continuous function on $ [0, 2] $ for which the right endpoint approximation with $ n = 2 $ is more accurate than Simpson's Rule.
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Calculus 2 / BC
Techniques of Integration
Missouri State University
University of Michigan - Ann Arbor
In mathematics, integration is one of the two main operations in calculus, with its inverse, differentiation, being the other. Given a function of a real variable, an antiderivative, integral, or integrand is the function's derivative, with respect to the variable of interest. The integrals of a function are the components of its antiderivative.
The definite integral of a function from a to b is the area of the region in the xy-plane that lies between the graph of the function and the x-axis, above the x-axis, or below the x-axis.
The indefinite integral of a function is an antiderivative of the function, and can be used to find the original function when given the derivative. The definite integral of a function is a single-valued function on a given interval. It can be computed by evaluating the definite integral of a function at every x in the domain of the function, then adding the results together.
In mathematics, a technique is a method or formula for solving a problem. Techniques are often used in mathematics, physics, economics, and computer science.
Sketch the graph of a cont…
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Okay, so this question wants us to find an approximation such that the error from the Simpson approximation is greater in the area of the Wraith approximation, which usually isn't the case. So to do this, let's just construct a graph. We don't need it necessarily define a rule for it. We just want something that messes with Simpsons Rule and really favors the right end point rule. So let's say that this is zero right here and this is one and this is 0.5. So let's say we have a function that's flat up until it reaches one, and then it's sort of spikes upto one, and then it stays there. So just by looking at this, we should see that the area the area is approximately 1.5. It's gonna be very close. So area should be close to 1.5 just a little bit less. But to find our approximations, let's do the right approximation first, which is Delta X Times effort two plus f of one. Remember, we skip the left point in a right some So Delta X is one f of two is one, and death of one is on half so the right approximation This 1.5, which is almost exactly what we think are real area is. But let's find the Simpson approximation. So the Simpson approximation is 1/3 time's half of zero plus four times after one plus effort, to which is 1/3 time's well f of zero, this 0.5 four times F of one, which is again 0.5 plus half of point to which again, we said, is one. So it's equal to 1/3 time's one 1.5 plus two. She's equaled a 3.5 over three, which is equal to about 1.16 So we see that are too is 1.5, and as to is 1.16 so and our actual is approximately 1.5. So are right. Good point is the better approximation.
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