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Problem

Sketch the graph of a function $ f $ that is cont…

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Problem 8 Easy Difficulty

Sketch the graph of a function $ f $ that is continuous on $ [1, 5] $ and has the given properties.

Absolute maximum at $ 4 $, absolute minimum at $ 5 $, local maximum at $ 2 $, local minimum at $ 3 $


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Related Courses

Calculus 1 / AB

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 4

Applications of Differentiation

Section 1

Maximum and Minimum Values

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Watch More Solved Questions in Chapter 4

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
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Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
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Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
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Problem 64
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Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
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Problem 75
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Problem 77
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Problem 80

Video Transcript

We want to sketch the graph of a function that is continuous on the interval 1 5 And has an absolute maximum at maximum at four. An absolute minimum at five. Local maximum at two in the local minimum at three. So we have a sketchy grant with those properties. Let's see The absolute maximum of course at four. First of all we see that the graphs continuous function. There is only one piece with no job or discontinuities. So it's a continuous function and it's a fine on the interval 15. Then we have an absolute um Maximum at four. We can see that this value here is the highest point on the whole domain of the function. The whole graph. So that's the absolute maximum in this case is also a local maximum. We have local maximum, Sorry, an absolute minimum at five. And we see here that the lowest point in the graph and the whole domain is This family here at five. We here we have an absolute any mom and then we have an absolute uh sorry, a local Minimum of three. Also local minimum three. We have or the only in this case the only local minimum Because if we see close to Valencia three, We know that the image of that .3 is the smallest value of the graph around these value three. But it's not the lowest the value of the whole graph because they're all lawless violence. They're sort of minimum is attained at five. But this is a local minimum of three. This part here now we have a local maximum up to so to have a local maximum here because if we look around two very near the value to, we have the highest point Or value in the graph corresponds to the image at two. See we have a local maximum and here we have a local minimum. That's it. We don't have any requirement at one. The important thing is that one, we have an image that is not and that is neither the absolute minimum nor the absolute maximum in order that The stream values are obtained at four and 5. And that's an example of the function fulfilling this for robert is here we can remark that two, we have an absolute maximum, but also in local maximum and that's it.

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Review

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