Question
Sketch the graph of a function $f$ where the domain is $(-2,2),$ $f^{\prime}(0)=-2, \lim _{x \rightarrow 2^{-}} f(x)=\infty, f$ is continuous at all numbers in its domain except $\pm 1,$ and $f$ is odd.
Step 1
This means that the slope of the function at $x=0$ is $-2$. We can represent this on the graph by drawing a tangent line at $x=0$ with a slope of $-2$. Show more…
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Sketch the graph of a function $f$ where the domain is $(-2,2)$, $f^{\prime}(0)=-2, \lim _{x \rightarrow 2^{-}} f(x)=\infty, f$ is continuous at all num- bers in its domain except $\pm 1$, and $f$ is odd.
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Sketch the graph of a function $ f $ where the domain is $ (-2, 2) $, $ f'(0) = -2 $, $ \displaystyle \lim_{x \to 2^-} f(x) = \infty $, $ f $ is continuous at all numbers in its domain except $ \pm 1 $, and $ f $ is odd.
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