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Let

$ f(x) = \sum_{n = 1}^{\infty} \frac {x^n}{n^2} $

Find the intervals of convergence for $ f, f', $ and $ f''. $

convergence is (-1,1)

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Joshua G.

May 21, 2021

Wouldn't f"(1) converge since it = lim n>>inf (1^(n-2)*(n-1))/n = lim n>>inf (n-1)/n = 0 ?

Joshua G.

May 21, 2021

Joshua G.

May 21, 2021

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