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Sketch the indicated curves and surfaces.Sketch the line in space defined by the intersection of the planes $x+2 y+3 z-6=0$ and $2 x+y+z-4=0$
Calculus 3
Chapter 29
Partial Derivatives and Double Integrals
Section 2
Curves and Surfaces in Three Dimensions
Partial Derivatives
Johns Hopkins University
Oregon State University
Baylor University
University of Nottingham
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The problem we have equations X plus two, Y plus, treated minus six equals zero. This is equation one, so this is equation one and this is equation two. So the situation to is two, X plus Y plus get minus 40 equals zero. So we have the introduction of these two planes is drawn in three dimensional figure. Is this? So this is the answer. Yeah, this is excesses, this is why access and this is their access.
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