00:01
Okay, let's try to sketch the region enclosed by those two curves.
00:05
And since the domain is specified, we only need to draw the curve inside the domain.
00:15
So our x -y plane.
00:19
This is not good.
00:22
So this is our xy plane.
00:27
Our x goes from negative pi over 3 to pi over 3 to pi over 3.
00:39
So the x equals power 3, tangent x equals to square root 3.
00:50
The x equals to negative power 3, tangent x equals to negative square root 3.
00:59
All right, x equals 0 is 0.
01:02
And we know tangent x is an odd function.
01:05
So it looks like this.
01:12
And for, on the other hand, for the second curve, our 2nd, 2x, you know, sine x look like this.
01:21
So we do only need to find the endpoints.
01:25
So endpoints is our x equals pi over 3.
01:28
We know sine x is square 3 over 2.
01:32
And we multiply it by 2.
01:33
So it will be square of 3.
01:35
As we can see, those two curves intersect at those two endpoint, also at origin.
01:45
Because 2xx is also an out of function.
01:49
So it looks like this.
01:53
And here is our enclosed region...