Question
Sketch the region bounded by the graphs of the functions and find the area of the region.$$f(y)=y^{2}, g(y)=y+2$$
Step 1
We set $f(y) = g(y)$ and solve for $y$: $$y^{2} = y + 2$$ This gives us $y^{2} - y - 2 = 0$. Factoring this equation, we get $(y - 2)(y + 1) = 0$. So, the points of intersection are $y = -1$ and $y = 2$. Show more…
Show all steps
Your feedback will help us improve your experience
Lucas Finney and 97 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Sketch the region bounded by the graphs of the algebraic functions and find the area of the region. $$ f(y)=y^{2}, g(y)=y+2 $$
Applications of Integration
Area of a Region Between Two Curves
Sketch the region bounded by the graphs of the functions and find the area of the region. $$ f(y)=y(2-y), g(y)=-y $$
Integration and Its Applications
The Area of a Region Bounded by Two Graphs
Sketch the region bounded by the graphs of the equations and find the area of the region. $$f(y)=y^{2}, g(y)=y+2$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD