Sketch the region enclosed by the given curves and calculate its area.
$ y = x^3 $, $ y = 0 $, $ x = 1 $
okay. We know we're only looking at the positive side because we know in this context, we can only have positive area. Okay, so now we over area is from 01 x cubed Jax. And I remember how we integrate increase The exploited by one's own. Just four instead of three were dividing by the new explain it, which is four now we're plugging in. This is officer just zero, Which means we have 1/4 is our solution.