00:01
Alright, let's sketch the region enclosed by those two curves first.
00:07
So here is our xy plane.
00:13
And now x equals to 2y square.
00:19
So it's a problem open to the right.
00:24
Okay, so it looks like this.
00:28
This is our x equals to 2y square.
00:34
And the second one also a problem is x equals to 4 plus y square.
00:47
So it's also open to the right.
00:53
And assume here is 4.
00:56
Since the coefficient is 1 instead of 2, which means this first curve will catch up with the second curve.
01:07
So they will have the intersection.
01:13
So assume the intersection is intersect here.
01:18
And this is symmetric by x -axis.
01:26
So eventually we'll get this moon ship enclosed area.
01:40
Okay.
01:43
And he observed that everything is represented by y.
01:48
It's like y is our independent variable here.
01:52
So to find this area, we'll take the integral with respect to y.
02:03
Okay, so then we need to find the boundary for y.
02:09
And as we see, i call this y1, this is our y2, so this is our y1, this is our y2 of the intersection point...