00:01
For this question, first let's draw the given curves.
00:08
Here is xy xxas, and this x equals to 1 minus y square.
00:19
So we know when y equal to 0, x equals 1.
00:23
So it equals 1.
00:24
It equals 1 at 0 this point.
00:29
Here is 1.
00:31
And since the coefficient before y is negative, you know, this problem, it opened to the left.
00:43
So look like this.
00:50
And y equal to x equal to 0, we know y goes to 1, negative 1.
01:03
And this is very symmetry.
01:09
To the first function.
01:12
When y equal to 0, this function equals to negative 1.
01:18
And since the coefficient of y square is 1 is positive, so it opened to the right.
01:25
And when x equals 0, y also equals 1 and negative 1.
01:35
So it looks like this.
01:39
And the enclosed region is in the middle here.
01:48
And for this question, as we can say everything is represented by y.
01:55
Our x can be represented by y.
01:58
The first curve is represented by y, and the second curve also represented by y.
02:04
So we decide to integrate with respect to y.
02:11
And once we want to integrate with respect to y, the typical approximating rectangle will go horizontal...