00:01
So for the double integral, the iterated integral given to us as the integral from 0 to 2 and then integral from 0 to 2 of 4 minus y squared, dy, dx, we have the region of integration, x going from 0 to 2, and y going from 0 to 2.
00:17
So we're integrating over a square region in the x, y plane.
00:21
This is going to be, we're integrating over a square from the origin to 2 to 2.
00:33
So the height function, the integrand here, 4 minus y squared, is a function of y only.
00:40
So it's going to be a parabola opening downward.
00:45
In the y direction, though, with the vertex at y equals zero and the value 4 decreasing to 0 and y equals 2.
00:54
So for the interpretation, over each vertical slice, x equals a constant...