00:01
So for this problem, it wants us to sketch the transition state structures involved in the reaction of hbr with one pentene.
00:11
And we also need to tell whether each structure resembles a reactant or a product.
00:18
So we're going to start off with the two bromopintane path.
00:32
And this will be, well, actually, let me move this down.
00:39
And transition state number one and then transition state number two.
00:55
So let's draw number one first for the two bromopentane path.
01:00
And so bear with me as i draw this.
01:05
It's not the easiest thing to draw.
01:10
A hydrogen, hydrogen.
01:18
This will be c3h7 and then a hydrogen.
01:26
And now to draw the actual states, right here will be a partial positive.
01:43
Right here will also be a partial positive.
01:49
And then transition state number two, this one's a little different.
01:53
We have carbon, which is bonded to c3h7, h3c, and then a hydrogen.
02:16
There's a positive charge on the carbon, and this is partially bonded to the bromine with a negative charge.
02:32
And then the one bromopentinance path, transition state number one, will be shown as carbon bonded to carbon, hydrogen, hydrogen, and then the c3h7 and the hydrogen...