Question
Sketch the vector-valued function on the given interval.$$\vec{r}(t)=\left\langle\frac{1}{10} t^{2}, \sin t\right\rangle, \text { for }-2 \pi \leq t \leq 2 \pi$$
Step 1
The x-component is given by: x(t) = (1/10)t^2 The y-component is given by: y(t) = sin(t) Now, we can plot the function on the given interval, -2π ≤ t ≤ 2π. Show more…
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