00:01
To find the vertex, focus, and directives of this problem, we're first going to rewrite it into standard form.
00:08
So let's begin by writing down the equation to x squared minus 2x, minus 4y minus 7, equals 0.
00:21
And to rewrite it into standard form, we're going to need to complete the square because there's a perfect square in the standard form of the parabola.
00:29
So we can complete the square in this part, x squared minus 2x, and the number we need to add is going to be half of negative 2 squared.
00:41
So half of negative 2 is negative 1.
00:43
Negative 1 squared is positive 1, so plus 1.
00:47
Because we're adding 1, to keep the equation unchanged, we're also going to subtract 1, and we'll still have the minus 4y minus 7.
00:59
All right.
01:01
So next we can factor this part, complete the square here.
01:04
This is factors into x minus 1 squared.
01:10
Next must combine this negative 1 here.
01:12
It's minus 1, which is minus 7.
01:14
We've still got minus 4y, but we're going to combine those two to make minus 8 and equal 0.
01:23
And next in standard form, we're going to get the x minus 1 squared by itself.
01:28
We're going to move everything else over to the right side.
01:31
So we'll have x minus 1 squared equals 4y plus 8.
01:40
And finally, i'm just going to factor out the 4, so that we'll have it in the form y minus something.
01:48
So it would be y plus 2.
01:50
That's right, yeah.
01:52
Now it's written as 1 squared equals 4 times y plus 2.
01:58
We can see the vertex right away...