00:01
In this question, we have got function, coss x.
00:08
First we have to create a table for the slope of the second.
00:13
Okay, and then we have to calculate the slope of the tangent using conjunction.
00:20
So let's start it.
00:22
First make the table.
00:23
So, in a option, we are going to discuss x from pi by 2 to 5 .2 to 5 .2.
00:38
2 plus 0 .1 okay so you have to calculate the slope of the sequence so that will be f pi by 2 plus 0 .1 minus f 5 by 2 divided by pi by 2 plus 0 .1 minus 5 by 2 is just canceling out so the values we are going to get here is essentially minus 0 .2 2995 minus 0 divided by 0 .1 so the value we are getting is minus 2 .995 so that is the slope of the second.
01:25
In second case x will be from pi by 2 to 5 by 2 plus 0 .01 so the slope in this case will be f 5 by 2 plus 0 .01 minus f of 5 by 2 divided by 1.
02:02
The value we are getting here essentially minus 0 .029 minus 0 divided by 0 .01.
02:17
So the average, sorry, the slope of the second we are getting as 2.
02:29
Sorry, in third case, x belongs to by 2x2 by 2 plus 0 .001.
02:41
We have to calculate the slope of the second in this case.
02:44
So that will be f of 5 by 2 plus 0 .0 .01 minus f of 5 by 2 divided by 5 by 2 plus 0 .00 minus 5 by 2...