00:01
For this problem, we have a bit of background information given, but what we really care about is, oh, actually, no, this is going to be relevant.
00:08
We're told that one of the many variables measured in a survey of mental health patients was frequency of social interaction on a five -point scale, where one is very infrequently, three is occasionally, and five is very frequently.
00:21
We have that the sample size, n, is 6 ,6181, and we have that the mean social interaction score, x bar is 2 .95, with a standard deviation, s, of 1 .1.
00:36
In part a, we are asked to conduct a hypothesis test at alpha equals 0 .01 to determine whether the true mean social interaction score of all connecticut mental health patients differs from three.
00:49
So we have that our null hypothesis here is that mu equals 3, the alternate hypothesis, that mu does not equal 3, and we have that we can use the z statistic because we have a sufficiently large value for n.
01:07
So z will be equal, or the critical value of z we can find from a table, something along those lines.
01:13
We'll find to be 2 .576 or specifically plus or minus 2 .576.
01:19
So we'll be able to reject if the absolute value of our z score is greater than 2 .576.
01:28
Let me fix that there.
01:29
2 .576.
01:32
Calculating the z score, we'll have that it would be x bar, 2 .95, minus mu, 3, divided by s, 1 .1, over the square root of n, so over the square root of 6 ,681...