Question
Sodium chloride $(\mathrm{NaCl})$ exhibits predominantly ionic bonding. The $\mathrm{Na}^{+}$and $\mathrm{Cl}^{-}$ions have electron structures that are identical to which two inert gases?
Step 1
Sodium (Na) has an atomic number of 11, so its electron configuration is 1s² 2s² 2pā¶ 3s¹. When it loses one electron to form Na+ ion, its electron configuration becomes 1s² 2s² 2pā¶, which is the same as neon (Ne), an inert gas with an atomic number of 10. Show more…
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