00:01
Right here we have the problem 102.
00:03
And for long questions like this, i always like to start by writing down the data that we know and then start solving the question.
00:13
So first we know the lattice energy for nalh equal to negative 887 kilojoules per mole.
00:24
And we know the heat up hydration for nalh is equal to negative 932.
00:34
32 kilojoules per mole.
00:40
And we know the mass of naaoh is equal to 25 gram.
00:49
Density of the solution is equal to 1 .05 gram per milliliter.
00:57
And the heat capacity is equal to 4 joules per gram per celsius degree.
01:10
And the initial temperature is equal to 20 degrees.
01:14
25 celsius degree and the boiling point is equal to 100 celsius degree.
01:25
So delta t equal to 100 minus 25, that's 75 degree.
01:32
All right, so the equation we know that delta h of the solution is equal to delta h of the solute plus the heat of hydration and delta h of solute is equal to negative energy of lattice.
02:06
So we have delta h solution equal to negative delta h lattice plus the heat of hydration.
02:26
So now we substitute numbers that is equal to negative, negative, 887 kilojouze per mole, plus negative 932 kilojoules per mole, and we get the delta h of the solution equal to negative 45 kilojoules per mole.
02:54
So that is the delta h of the solution...