Step 1:
The given reaction is:
$$
\mathrm{Na}(\mathrm{s})+1 / 2 \mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{NaCl}(\mathrm{s})
$$
In this reaction, sodium (Na) is losing an electron to become Na$^+$ and chlorine (Cl$_2$) is gaining an electron to become Cl$^-$.
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