00:01
For part a, let's first up by balancing the two redox equations.
00:06
Equation 1 is hno2 plus i minus to n0 and i3 minus.
00:19
We'll break this apart into t .f reactions.
00:22
We get hno2 to no.
00:28
Balance the oxygen.
00:32
Balance the hydrogen and we'll balance the charge by any one electron here and second half reaction i minus to i3 minus three there to balance the iodine and two electrons to balance the charge we're going to double the first half reaction to be a will they cancel out the electrons.
01:13
And balanced, we get 2hno2 add 3i minus to 2n0, i3 minus, and 2h2o.
01:25
So here's our first half reaction, sorry, our first reduct reaction that is balanced.
01:31
And let's balance the second equation.
01:37
Second one will be i3 minus add s2o3 .3.
01:43
2 minus to i minus and s 406 to minus break this apart into two half reactions put a three here to balance the iodine and two electrons to balance the charge s2 oh 3 to minus to s 4 oh 62 minus to s 4 oh 6 2 minus we put a 2 here to balance the sulfur.
02:21
And oxygens are already balanced...