Question
Solids of revolution Let R be the region bounded by the following curves. Find the volume of the solid generated when $R$ is revolved about the given axis.$y=\sqrt{\sin x}, y=1,$ and $x=0 ;$ about the $x$ -axis
Step 1
Solve sqrt(sin x) = 1 ⇒ sin x = 1 ⇒ x = π/2 (first positive intersection). With x = 0 as the left boundary, the region is between y = sqrt(sin x) (lower) and y = 1 (upper) for 0 ≤ x ≤ π/2. Show more…
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