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Solve an equilibrium problem (using an ICE table) to calculate the pH of each solution.

a. a solution that is 0.195 M in HC2H3O2 and 0.125 M in KC2H3O2b. a solution that is 0.255 M in CH3NH2 and 0.135 M in CH3NH3Br

(a) 4.54(b) 10.91

Chemistry 102

Chapter 17

Aqueous Ionic Equilibrium

Section 5

Solubility Equilibria and the Solubility-Product Constant

Liquids

Aqueous Equilibria

Carleton College

Rice University

University of Toronto

Lectures

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So now we'LL do problem twenty eight from chapter seventeen. So in this problem, it asks us to calculate the pH of two solutions and two different cases so we can go ahead and work on question A problem, eh? So here is telling us that we have acetic acid, which is a tch see to H three. Oh two. We have it in water and we also have at beginning, um, some of the product of the contra bass, which is h too. See to age three Oh, two minus, which is the acid ate so we can go ahead and draw the ice table here under the reaction. Excuse me. So we have three initial concentrations given in the problem. And so we just need to write down here our initial our change in our equilibrium. So the initial given for acetic acid zero point one nine five you don't take into account water each the others know additional initial H three a plus and the initial for the estate on a zero point one two five want. So the changes minus X plus X and plus X and so that gives us an equilibrium concentration of acetic acid of zero point one nine five minus x x and zero point one two five plus six. So now we need to set our products over our reactant equal to Okay, So if you don't know, OK, ay, you can usually find them in the appendix of the book. And for acetic acid, it's two point eight one go and change colors here is equal to the product over the reactant. So zero point one two five plus eggs times X, which is our concentration of hegemony. Um, then we have zero point one nine five minus six. So, since this is a week after, we're going to use our excess small approximation and eliminate the plus six and minus X so he gets Europe went one to five x over zero point one nine. So then what we need to do is solve for X so way. Multiply two point eight one time scented minus five by zero point one nine five and divide by zero point one two five and then we get X is equal to one point eight times ten to the minus five. So this here is equal to a concentration of hydro ni um So if we do the negative log of eggs, we get four point five five, which is our pH. Okay, so now we can go ahead and look at part B of this question and for that one were given a slightly different situation. So we have this method. I mean, So this is ch three an age to and that will react with water to give c H three n age three plus. So the metal ammonium and the hydroxide so we can go ahead and write our eye stable here underneath the reaction. So for ch three image to we have zero point two five five initially present. Don't take water into account. And we have zero point one two three five of the consequent acid, methyl ammonium and no hydroxide. So once again, they have negative axe here plus x wass X. So our equilibrium a zero point two five five mine is eggs zero point one two three five plus x and X. So Oh, we went Now we need Thio once again. Look at the appendix if we don't know the value, but we need a k b, a k b for our base c'est rien age too. And so the K B is equal to from the appendix of the book four point four times, ten to the minus for and so this is once again able to our products over the reactant your point one three five plus x times x over zero point two five five minus x. So since this is a weak base on, we can always check at the end if we need to on if it's correct. But we can use our X a small approximation. So we eliminate the edition and plus of the the eggs and we get zero point one three five thanks over zero point two five. So once again, we solve for the answer for eggs. Bye. Multi plane zero point two five five times R k b and dividing by zero point one three five. And this gives us a point three one times ten to the minus. For So now this gives us the concentration of hydroxide so we can find mph directly from this. So what we do is we do the concentration of H three o we use. The relationship with water is equal to the K W one times ten to the minus fourteen divided by the concentration of hydroxide, which we just calculated. Eight. Aim point three one times ten to the minus four. Kim And so if we draw answer over here, that gives us a concentration of hydro ni um as being one point two zero times ten to minus eleven. And so, if we want to our final answer here for PH. We just need to take the negative log of the hydro ni um, which is one point two times ten to the minus eleven, and this is equal to ten point nine two. So a basic pH. Because we have more of the base here in the clinch it acid.

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