00:01
In this problem, we're being asked to solve the given equation for x.
00:03
Well, in order to do that, the first thing we need to do is to get our light terms on the same side.
00:08
So i usually begin by getting my variable terms on the left -hand side.
00:12
So to move our 2x term to the left -hand side of the equation, i'm going to subtract 2x from both sides, because 2x minus 2x is 0, so these will cancel.
00:21
So now we have 5 minus 2x, which is 3x, plus 2 is equal to negative 10.
00:27
Okay, so now what we need to do is get our x term all by itself.
00:32
So in order to move that positive 2 to the right -hand side, we'll subtract 2 because 2 minus 2 is 0, so these will cancel.
00:40
So this leaves us with 3x is equal to, well, negative 10 minus 2 is negative 12...