00:01
So in the given question we are given a function f of x is equal to 86 .3 times the natural log of x minus 680.
00:19
And it is given that f of x represents the percent of percentage of snow.
00:32
So f of x represent the percent of snow and x is the altitude in feet.
00:45
So the function represents the percentage of snow in a place at x feet, right? so this is the function.
00:59
Now we are given different altitudes.
01:03
The first one of which is 3 ,000 feet right they are asked to find the percentage of snow at 3 ,000 feet so let's substitute 3 ,000 for x in the function so f of 3 ,000 is equal to 86 .3 times natural log of 3 ,000 plus 6 minus 680 so the natural log of 3000 is 8 so 86 .3 times 8 minus 680 which would give us 690 .95 minus 680.
02:05
So the percentage of snow at 3 ,000 feet is 10 .95.
02:22
And we are told to find the percentage of snow.
02:27
Next at 4 ,000 feet.
02:32
So the same procedure again...