00:01
In this problem, we have d, y, dx is equal to 4e to the x over y.
00:11
And i just like to think of this as cross multiplication, especially a problem like this, because a lot of students are really good at cross multiplying, that one cross product would be y times d, y, and then the other cross product would be 4e to the x times dx.
00:28
And it just makes sense.
00:30
It helps a lot of students that are really struggling with this.
00:33
So you can integrate both sides where you add one to the exponent, multiplied by the reciprocal of your new exponent.
00:39
The derivative of 4e to the x is 4e to the x.
00:43
So it makes sense that this is also 4e to the x when you integrate.
00:48
And you need a plus c somewhere in your problem...