00:01
We are given the differential equation, d .y, d .x, is equal to this giant quotient of x squared plus x plus one all over x.
00:13
Now, i'm assuming that you're pretty familiar with the, you can treat it like a cross multiplication to get dx over.
00:21
And while i'm at it, i would actually rewrite this instead of all of it divided by x.
00:28
I'm in the habit of, like, dividing each piece by x.
00:32
So then when we go to look at the next step under this in green, it would be the integral of 1dy is equal to the integral x squared divided by x is just x plus 1.
00:46
And then i would actually leave that as 1 over x d x.
00:50
So hopefully you're following along pretty well, because on the left side, the integral of 1dy is just y...