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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86

Problem 75 Hard Difficulty

Solve each equation, and check your solutions.
$$(x+3)^{2}-(2 x-1)^{2}=0$$

Answer

$\left\{-\frac{2}{3}, 4\right\}$

Related Courses

Algebra
Beginning and Intermediate Algebra

Chapter 5

Factoring and Applications

Section 5

Solving Quadratic Equations by Factoring

Related Topics

Whole which of Numbers

Polynomials

Exponential and Logarithmic Functions

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Watch More Solved Questions in Chapter 5

Problem 1
Problem 2
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Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72
Problem 73
Problem 74
Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85
Problem 86

Video Transcript

first I need to do here is square each binomial. Remember, this is the same as having the same binomial twice, so that would foil to be X squared. I have outers intercepted the same so it's always two times that. Products that would be plus six x plus nine do the same thing. But here I have to be careful because of the minus, and I'm going to keep that in parentheses, the before X squared, multiply and double because there's gonna be two of the same things that we minus four X plus one again. You can just write it twice and foil that distribute the negative. So X squared plus six x plus nine minus four X squared plus four x minus one equals zero. Combine your like terms. I always like my square term to be positive, so I'm going to factor out a negative one. So I'm gonna have negative one times three X squared, minus 10 x minus eight equals zero. Next, they have to factor the try. No meal. That's left amount of room here. So let's go up here. So I'm still going to have that negative one and then I'm going to factor the try no meal and I'll try three x and x. Ah, I know I have to have different signs for the eight, so we'll have plus two and minus four. Let's double check years. That would be positive, too. And negative 12. Which would give me the correct, um, middle negative one can't make it zero, so I don't have to worry about that. But I know either three X plus two could be zero. Let's finish that. So three X equals negative, too. So one answer is negative. 2/3 the other one x minus four could be zero. So X could be four. So those to be my two solutions.

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Beginning and Intermediate Algebra

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