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Solve each equation. Check your solutions.$$2+\frac{5}{3 x-1}=\frac{-2}{(3 x-1)^{2}}$$
$\left\{-\frac{1}{3}, \frac{1}{6}\right\}$
Precalculus
Algebra
Chapter 11
Quadratic Equations, Inequalities, and Functions
Section 4
Equations Quadratic in Form
Introduction to Conic Sections
Equations and Inequalities
Functions
Polynomials
Missouri State University
Harvey Mudd College
Idaho State University
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For exercise 67 I'm going to sub you for three X +13 x minus one. And we can write this as two plus five over U equal to negative two U squared. And then multiply everything by U squared. Where we'll have two U squared plus five. You Plus two equal to zero. Then we could solve for you but we'll have to and one with positive So you can equal negative two or negative one half. And now using back substitution we have three X minus one equal to negative two and three x minus one equal to negative one half. So this means three x can equal negative one. So x equals negative 1 3rd and we have three x equal to one half. So this means X. Can you cool 16 and checking to see if these were within feasible limits. It is So these are these solutions.
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