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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85

Problem 14 Easy Difficulty

Solve each equation. Check your solutions.
$$
\frac{2}{m}+\frac{3}{m+9}=\frac{11}{4}
$$

Answer

Related Courses

Precalculus

Algebra

Beginning and Intermediate Algebra

Chapter 11

Quadratic Equations, Inequalities, and Functions

Section 4

Equations Quadratic in Form

Related Topics

Introduction to Conic Sections

Equations and Inequalities

Functions

Polynomials

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Watch More Solved Questions in Chapter 11

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Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
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Problem 44
Problem 45
Problem 46
Problem 47
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Problem 50
Problem 51
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Problem 53
Problem 54
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Problem 73
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Problem 75
Problem 76
Problem 77
Problem 78
Problem 79
Problem 80
Problem 81
Problem 82
Problem 83
Problem 84
Problem 85

Video Transcript

For Exercise 14. We're going to multiply everything by our 23 denominators. So we'll have eight a.m. Plus 72 plus 12 and equal to 11 a.m. squared plus 99 grouping or like terms will have 99 and -20 am was 79 M minus 72. Well it's plus 79 in an assembly to equal Syria. Alright, so now we can factor this out, we'll have 11 in and and but this was eight, That would be 88 am positive. So we need to take away nine from it. But and that satisfies our conditions. Therefore, n equals -8 or 9 11th. And we're going to check to see if our solutions are correct. So that's going to be two over negative eight plus three over one Equal to 11/4. Um We could also write that with a denominator before as negative one plus 12 equals 11 4th And that means 11/4 equals 11/4. Now let's try it with 9/11. So it's It's going to be 22. 9ths plus three over 9, 11th plus nine equals 11 4th in other words, or have 33 Over 108. And so mhm We can divide I believe 108 53 For T. equals 36. So we'll have 36 here for now this will be 11 plus In 22 times four is 88. So it's going to be 99/36 equals 11/4. Now if we divide everything by nine, that's going to be Going to be 11 of her. four equals 11/4. So both of our original solutions are correct.

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Margaret L. Lial , John Hornsby

Beginning and Intermediate Algebra

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