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Solve each equation. Check your solutions.$$\frac{3}{2 x}-\frac{1}{2(x+2)}=1$$

$\left\{\frac{-1 \pm \sqrt{13}}{2}\right\}$

Precalculus

Algebra

Chapter 11

Quadratic Equations, Inequalities, and Functions

Section 4

Equations Quadratic in Form

Introduction to Conic Sections

Equations and Inequalities

Functions

Polynomials

Campbell University

Harvey Mudd College

Baylor University

Idaho State University

Lectures

01:43

In mathematics, a function…

03:18

03:44

Solve equation, and check …

01:29

Solve each equation. Check…

01:16

Solve each equation.$$…

06:44

01:38

01:49

Solve and check each equat…

01:10

00:59

01:13

Solve each equation, and c…

05:57

03:15

00:16

02:19

Solve each equation.

00:48

02:10

00:45

11:42

07:14

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01:02

Find the solution set to e…

for Exercise 17. We're going to have two multiplied by two X. And X plus two. Therefore three it's going to be multiplied by X plus two. So that'll be three X plus six minus X equals two X squared plus four X. Bringing everything to the right hand side. We have two X squared plus two X -6 equals zero. Now this is not fact fact arable. So we're going to have to use the quadratic formula. So expo equal negative two plus or minus square root B squared minus four A C over chile. So simplifying this, we have negative two plus or minus Square root of 52 over four. Now we can rewrite that again as negative two plus or minus and from 50 to I know there's a that's it's possible to get out of two from there. So this would be two square root of 13 over four which we can simplify two negative one plus or minus Square root of 13 over to. Okay, so if that's the solution and we need to check for it, we are largely going to use our calculator. So we have 3/2 and This would be multiplied by a negative one minus route 13 over to minus one over. I'm just going to write plus or minus minus one over two. -1 plus or minus root 13 Over 2-plus 2 equal to one. Mhm. Well when you have this in your calculator it does check out and maybe we can take the first few steps to try and to try and solve it just to see what it looks like. Oh, they're given the radical. I think it's safe to leave it as is.

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