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Problem

Solve each equation, if possible. $$ 5 x=4 x+7 $$

00:42

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86 Problem 87 Problem 88 Problem 89 Problem 90 Problem 91 Problem 92 Problem 94 Problem 95 Problem 96 Problem 97 Problem 98 Problem 99 Problem 100 Problem 101 Problem 102 Problem 103 Problem 104 Problem 105 Problem 106 Problem 107 Problem 108 Problem 109 Problem 110 Problem 111 Problem 112 Problem 113 Problem 114 Problem 115 Problem 116 Problem 117 Problem 118 Problem 119 Problem 120 Problem 121 Problem 122 Problem 123 Problem 124

Problem 64 Medium Difficulty

Solve each equation, if possible.
$$
2(3 x)-5(3 x+1)=58
$$

Answer

$x=-7$

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Elementary and Intermediate Algebra

Chapter 2

Equations, Inequalities, and Problem Solving

Section 2

More about Solving Equations

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Video Transcript

Okay, we have two times. Three AKs, minus five times three x plus. One equals 52. 58. Excuse me. So we want to go ahead and just start multiplying and distributing where we can. So two times three exes, six x and the negative five times three x would be negative. 15 axe and negative. Five times. One would be negative. Five equals 58. Let's go ahead and collect, like terms. So six minus 15 ex. Those are, uh those were both exits. Sort of negative. Nine x minus five equals 58. And then I want to unravel this. So I'll add five to clear out the minus five. And I get negative. Nine X equals 63. Since I want to divide by negative nine, that will clear out my multiplication. And I end up with X equals negative seven. I can't want to check that. This works. So too. Times three times negative. Seven minus five times, three times Negative. Seven plus one. Is that equal to 58? Okay, we'll start simplifying this down, so ah, two times. Negative. 21 minus five times. Let's go ahead and do this all in one fell swoop. I have negative 21 plus one. So negative 20. Is that equal to 58? This is negative. 42. This is positive. 100. Is that equal to 58? Yes, 58 equals 58. So x equals negative seven.

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Alan S. Tussy, R. David Gustafson

Elementary and Intermediate Algebra

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